A nontrivial slope
on a knot
in
is called a characterizing slope if whenever the result of
–surgery
on a knot
is orientation-preservingly homeomorphic to the result of
–surgery
on
, then
is isotopic to
. Ni and Zhang ask: for
any hyperbolic knot
,
is a slope
with
sufficiently large a characterizing slope? In this article, we prove that if we can take an
unknot
so
that
–surgery
on
results
in
and
is not a
meridian of
,
then
has
infinitely many noncharacterizing slopes. As the simplest known example, the hyperbolic,
two-bridge knot
has no integral characterizing slopes. This answers the above question in the
negative. We also prove that any L-space knot never admits such an unknot
.
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