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Abstract
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Let A be a self-adjoint operator
on a Hilbert space H satisfying mI ≦ A ≦ MI, 0 < m < M. Set q = M∕m. Let j
and k be real numbers, jk≠0, j < k. Then for all x ∈ H(x≠0). Letting j = −1 and k = 1, this inequality reduces to
(Ax,x)(A−1x,x) ≦ [(M + m)2∕4mM](x,x)2, the well-known Kantorovich
Inequality.
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Mathematical Subject Classification
Primary: 47.10
Secondary: 47.40
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Milestones
Received: 11 March 1965
Published: 1 July 1966
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