Of fundamental importance to
the study of subnormal subgroups is the following result of Wielandt:
Let A and B be subnormal subgroups of a group G such that A is normal in
A ∪ B. Then A ∪ B is subnormal in G.
The usual proof of Wielandt’s result depends on the construction by conjugation
of a special subnormal series from A to G. It would be of interest to obtain a proof
which uses only the given subnormal series, without explicit dependence on
conjugation, and valid in algebraic systems other than groups.
This note presents, in the more general context of a lattice with the normality
relation introduced by R. A. Dean, a proof of the analogous result in case either A or
B has defect three or less.
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