Let all the zeros of a
polynomial p(z) of degree n lie in |z|≦ 1. Given a complex number a what is the
radius of the smallest disk centred at α containing at least one zero of the polynomial
((z − a)p(z))f? According to Theorem 1 the answer is (|a| + 1)∕(n + 1) if
|α| > (n + 2)∕n. Theorem 2 which states that if both the zeros of the quadratic
polynomial p(z) lie in |z|≦ 1 and |a|≦ 2 then ((z − α)p(z))′ has at least one zero
in