We give two proofs
that H2(SL(3,3),F33) = 0. This result has appeared in a paper by Sah, [6],
but our methods are relatively elementary, i.e., we require only elementary
homological algebra and do a group-theoretic analysis of an extension of
SL (3, 3) by F33 to show that the extension splits. The starting point is
to notice that the vector space is a free module for F3(⟨x⟩), where x has
Jordan canonical form . We then can exploit the vanishing of
Hi(⟨x⟩,F33) i = 1,2.