Recall f : D → R2 is a Nash
function if f is analytic and if there exists a polynomial pf(x,y,z)≢0 with
pf(x,y,f(x,y)) = 0 for all (x,y) in D. We wish to show Theorem 1: If D is a
semi-algebraic simply connected, open domain in R2, then D is Nash isomorphic to
R2. This means that there exists a map (x,y) → (f1(x,y),f2(x,y)) where f1 and f2
are Nash functions on D and the map is a Nash isomorphism of D with
R2.
As a corollary, we obviously get ND≅NR2 where ND = {f : D → R|f is a Nash function on D}.
Moreover, if D is any connected semi-algebraic domain in R2, it follows that D is
Nash isomorphic to R2 minus n points where n = the number of holes in D. Here a
domain is always considered to be open. The problem of classification of nonopen
regions even in the plane is much more complicated and not settled as far as I
know.
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