In this paper we prove that
every separable metric space X with transfinite dimension IndX has metric
compactification cX such that
where ind X (Ind X) denotes small (large) inductive transfinite dimension, and
D(X) denotes the transfinite D-dimension. More generally, let T be a set of
invariants (ind,Ind,D). We consider the following problem:
Let R ⊆ T and X be a metric space. Does there exist a bicompactum (complete
space) cX ⊃ X such that
When it is not so, we give counterexamples. We give also necessary and sufficient
conditions of the existence of transfinite dimensions of separable metric space in
terms of compactifications.
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