It is shown that a
Banach lattice X has Pelczynski’s property (V∗) if and only if X contains
no subspace isomorphic to c0. This result is used to show that there is a
Banach space E that has Pelczynski’s property (V∗) but such that its dual E∗
fails Pelczynski’s property (V), thus answering in the negative a question of
Pelczynski.