We show that for α ≥, the
following inequality holds:
for every function g on (−1,1) satisfying ∥g∥2=∫−11(1 − x2)|g′(x)|2dx < ∞ and
∫−11e2g(x)xdx = 0. This improves a result of Feldman et al., 1998, and answers a
question of Chang and Yang in the axially symmetric case.