Let K be any field, let
K(x1,…,xn) be the rational function field of n variables over K, and let Sn and An
be the symmetric group and the alternating group of degree n, respectively. For any
a ∈ K ∖{0}, define an action of Sn on K(x1,…,xn) by σ ⋅ xi = xσ(i) for σ ∈ An and
σ ⋅ xi = a∕xσ(i) for σ ∈ Sn ∖ An. We prove that for any field K and n = 3,4,5, the
fixed field K(x1,…,xn)Sn is rational (that is, purely transcendental) over
K.
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