Abstract
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The group of homeomorphisms of the closed interval that are absolutely continuous and
have an absolutely continuous inverse was shown by Solecki to admit a natural Polish group
topology
.
We show that under mild conditions on a compact space endowed
with a finite Borel measure such a topology can be defined on the
subgroup of the homeomorphism group consisting of those elements
such
that
and
preserve the class of null sets.
We use a probabilistic argument to show that in the case of a compact topological
manifold equipped with an Oxtoby–Ulam measure, as well as in that of the Cantor
space endowed with some natural Borel measures, there is no group topology between
and the
restriction
of the compact-open topology. In fact, we show that any separable group topology strictly finer
than must be
also finer than
.
For one-dimensional manifolds we also show that
and
are the only Hausdorff group topologies coarser than
, and
one can read our result as evidence for the nonexistence of a good notion of regularity
between continuity and absolute continuity.
We also show that while Solecki’s example is not Roelcke precompact, the group of
absolutely bicontinuous homeomorphisms of the Cantor space endowed with the
measure given by the Fraïssé limit of the class of measured boolean algebras with
rational probability measures is Roelcke precompact. This can be interpreted as
showing the nonexistence of a good notion of regularity between continuity and
absolute continuity.
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Keywords
group topology, absolutely continuous, homeomorphism group
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Mathematical Subject Classification
Primary: 57S05, 57Sxx
Secondary: 28-XX
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Milestones
Received: 6 October 2025
Revised: 26 February 2026
Accepted: 16 March 2026
Published: 10 August 2026
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| © 2026 The Author(s), under
exclusive license to MSP (Mathematical Sciences Publishers).
Distributed under the Creative Commons
Attribution License 4.0 (CC BY). |
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